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最佳答案:解(拉格朗日乘数法):设F=xy+λ(x+y-1)令Fx=y+λ=0........(1)Fy=x+λ=0........(2)Fλ=x+y-1=0......
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最佳答案:f'(x)=cosx+sinx+1>0 单调增加cosx+sinx+1=0cosx+sinx=-1+√2(x+45°)x=45°时有极值√2-1