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最佳答案：拉格朗日中值定理得到lnx-ln1/(x-1)>1/y>1/x所以(x-1)/(lnx-1)(x+1)/2只有拉格朗日中值定理不足以解决问题还要用到lnx的其它
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最佳答案：f(π/2)-f(0)=1F(π/2)-f(0)=π/2-1[F(π/2)-F(0)]/[f(π/2)-f(0)]=π/2-1g(x)=F`(x)/f`(x)=
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最佳答案：The differential mean value theorem is a series of mean value theorems in genera