-
最佳答案:不知道是不是你想要的#includedouble fun(int m){int i=1;double sign=-1;double s=1;while(i++
-
最佳答案:printf("f=%fnn",f);out=fopen ("outfile.dat","w");
-
最佳答案:Function sum(n) As Doublesum = 0For i = 1 To nIf i Mod 2 = 0 Then sum = sum + i
-
最佳答案:Private Function fun(ByVal a As Integer, ByVal b As Integer) As Integers = 0For
-
最佳答案:#include <conio.h>#include <stdio.h>double fun(int m){ double t=1.0;int i=2;for(
-
最佳答案:(2.0*i)(2.0*i) 应该是:(2.0*i)*(2.0*i) 吧
-
最佳答案:Private Sub Command1_Click()x = Text1.Texts = 1a = 1Dok = k + 1a = a * -1 * x ^
-
最佳答案:#includedouble fun(int m){double y=1.0;int i; //i改为小写//y+=1.0/(i*i); //1改为1.0ret