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最佳答案:xy=e^x-e^yd(xy) = d(e^x-e^y)xdy + ydx = e^xdx - e^ydy(x+e^y)dy = (e^x-y)dx则由dy/d
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最佳答案:两边对x求导dy/dx=-e^y-xe^ydy/dxdy/dx=-e^y/(1+xe^y)
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最佳答案:原方程是xy=1-e^y?如果是的话 将等式两边对X求导数得y+xy'=e^y*y'则 y‘=y/(e^y-x)y'(0)=y/e^y
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最佳答案:e^y=y+xe^y·y'=y'+1y'=1/(e^y-1)∴dy/dx=1/(e^y-1)即dy/dx=1/(x+y-1).y'=1/(x+y-1)y''=-