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最佳答案:int Count (double a[],int n){int num=0;int i;double avg;int sum=0;for (i=0;i
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最佳答案:void main(){int n[5][5]={ {1,2,3,4,5},{-1,-2,-3,-4,-5},{1,2,3,4,5},{-1,-2,-3,-4,
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最佳答案:double fun(){double a[4][4];double sum = 0;int i,j;for(i=0;i
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最佳答案:#includeint a[10];int num1=0,num2=0,num3=0;int sum1,sum2;int main(){int i;sum1 =