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最佳答案:y=(x²-2x+2)×e^4xy'=[(x²-2x+2)]'×e^4x+(x²-2x+2)×(e^4x)'=(2x-2)×e^4x+(x²-2x+2)×4e^
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最佳答案:f(x) = ∫ f'(x) dx = x³/3 + 2x² + cf(-3) = -9 + 18 + c = 10c = 1f(x) = x³/3 + 2x²