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最佳答案：网上有很多高数课后习题答案,你可以下载一个参考~e^y-e^x=xy两边求导,得e^y*y'-e^x=y+xy'(e^y-x)y'=(e^x+y)所以y'=(e
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最佳答案：两边对x求导：y'=(1+y')[sec(x+y)]^2得y'=[sec(x+y)]^2/{1-[sec(x+y)]^2}=1/{[cos(x+y)]^2-1}
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最佳答案：e^x-y'e^y=cos(xy)y'y'=e^x/(cos(xy)+e^y)y'|x=0=1/(1+e^y)
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最佳答案：令x=0,代入方程e^y+xy=e得e^(y(0))+0×y(0)=e,化简为e^(y(0))=e所以y(0)=1因此y^n(0)=1
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最佳答案：设y=f(x)是由方程e^x+y+xy^2=1确定,x=0代入,得1+y=1y=0两边同时对x求导,得e^x+y'+y²+2xyy'=0x=0,y=0同时代入,
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最佳答案：dcos(xy)=dx-sin(xy)d(xy)=dx-sin(xy)(ydx+xdy)=dx-ysin(xy)dx-xsin(xy)dy=dxdy=-[ysi
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最佳答案：x=0则y+y=ey=e/2y+ye^x=edy+dye^x=dedy+e^xdy+y*e^xdx=0所以y'=dy/dx=-y*e^x/(1+e^x)所以y'
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最佳答案：方程两边同时求x对y的导：y+xdy/dx+1/x+2ydy/dx=0,dy/dx=-(y+1/x)/(x+2y),dy=-(y+1/x)dx/(x+2y)
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最佳答案：x=0则lny=0y=1两边对x求导[1/(x²+y)]*(x²+y)'=3x²+cosx(2x+y')/(x²+y)=3x²+cosxy'=(x²+y)(3x
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最佳答案：x+y+z=ez两边对x求导:1+dz/dx=e^z * dz/dx即dz/dx=1/(e^z-1)再次两边对x求导：d^2z/dx^2=-e^z *(dz/d