a+b=根号10
ab=2
a²-ab+b²
=(a+b)²-3ab
=10-6
=4
|a-b|
=根号[(a-b)²]
=根号[(a+b)²-4ab]
=根号(10-8)
=根号2
所以log4(a2-ab+b2)/|a-b|
=log4 (4)/根号2
=1/根号2
=2分之根号2
a+b=根号10
ab=2
a²-ab+b²
=(a+b)²-3ab
=10-6
=4
|a-b|
=根号[(a-b)²]
=根号[(a+b)²-4ab]
=根号(10-8)
=根号2
所以log4(a2-ab+b2)/|a-b|
=log4 (4)/根号2
=1/根号2
=2分之根号2