Question

函数1/根号(1-2x)求导,判断其单调性.

Answer 1

用求导公式求导呗

f（x）=1/√(1-2x),且√(1-2x)大于0.

则f'(x)=-(√(1-2x))'/(√(1-2x)）^2

=-(√(1-2x))'/(1-2x)

=-1/2√(1-2x)*(-2) / (1-2x)

=1/(√(1-2x)）^3

则f'(x)>0.所以单调递增