解下列方程3(X-1)+5=8 5X-3(X+3)=110-(X+1)=2(X+2) 2(X+1)-3(X-3)=93(

2个回答

  • 3(X-1)+5=8

    3x-3+5=8

    3x=8-5+3

    3x=6

    x=2

    5X-3(X+3)=1

    5x-3x-9=1

    2x=1+9

    2x=10

    x=5

    10-(X+1)=2(X+2)

    10-x-1=2x+4

    9-x=2x+4

    9-4=2x+x

    5=3x

    x=5/3

    2(X+1)-3(X-3)=9

    2x+2-3x+9=9

    -x=9-9-2

    -x=-2

    x=2

    3(Y+2)-6=2+5(Y+2)

    3Y+6-6=2+5Y+10

    3Y=12+5Y

    12=-3Y+5Y

    12=2Y

    Y=6

    2(3X-1)-3(4X+3)=X-4(X-1)

    6x-2-12x-9=x-4x+4

    (6x-12x)+(-2-9)=-3x+4

    -6x-11=-3x-4

    -4-11=-3x+6x

    -15=3x

    x=-5

    10X-4(3-X)-5(2+7X)=15X-9(X-2)

    10x-12+4x-10-35x=15x-9x+18

    (10x+4x-35x)+(-12-10)=6x+18

    -21x-22=6x+18

    -18-22=6x+21x

    -42=27x

    x=-42÷27

    x=-42/27

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