2log3(1/2)+log3(12)-(0.7)^0+0.25^-1 0
2个回答
=log3(1/2)^2+log3(12)-1+4
=log3[(1/4 )*12]-1+4
=log3(3)-1+4
=1-1+4
=4
相关问题
原式=0.064^(-1/3)-(-1/8)^0+16^3/4+0.25^1/2+2log3(6)-log3(12) 那
log7[log3(log1/2x0]=0 求x
0.064^-1/3-(-1/8)^0+7log7^2+0.25^2/5·0.5^-4
解方程log4(3-x)+log0.25(3+x)=log4(1-x)+log0.25(2x+1).
解方程log4(3-x)+log0.25(3+x)=log4(1-x)+log0.25(2x+1).
比较3^1/3,log0.2(0.3),2.2^1/3,log2(0.9)的大小,
指对数比较大小问题(1)2^0.3,0.3^2,log2 0.3;(2)log1/2 0.4,lg0.4,log2 0.
比较log(1/2)0.3,log(3)0.2的大小
log2(log0.5(log2a))=0 log3(log1/3 (log3 b))=0 a,b的大小关系为?R
化简log2(1+2^0.5+3^0.5)+ log2(1+2^0.5-3^0.5)