limx/(x+1)arctanx=怎么做能?
1个回答
是x→0吗?
lim(x→0)x/[(x+1)arctanx]
=lim(x→0)x/[arctanx]*lim(x→0)1/(x+1)
=lim(x→0)x/x*lim(x→0)1/(x+1)
=1
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