Question

log(2)5×log(5)81×log(3)4＋In√e.

Answer 1

log(2)5×log(5)81×log(3)4＋In√e

=log(2)81×log(3)4＋1/2

=4log(2)3×2log(3)2＋1/2

=8+1/2=8.5

(log(2)3＋log(4)9)(log(3)4＋1／2log(3)2)

=(log(2)3＋log(2)3)(2log(3)2＋1／2log(3)2)

=2log(2)3*3/2log(3)2)

=3

换底公式的应用.