log(2)5×log(5)81×log(3)4+In√e
=log(2)81×log(3)4+1/2
=4log(2)3×2log(3)2+1/2
=8+1/2=8.5
(log(2)3+log(4)9)(log(3)4+1/2log(3)2)
=(log(2)3+log(2)3)(2log(3)2+1/2log(3)2)
=2log(2)3*3/2log(3)2)
=3
换底公式的应用.
log(2)5×log(5)81×log(3)4+In√e
=log(2)81×log(3)4+1/2
=4log(2)3×2log(3)2+1/2
=8+1/2=8.5
(log(2)3+log(4)9)(log(3)4+1/2log(3)2)
=(log(2)3+log(2)3)(2log(3)2+1/2log(3)2)
=2log(2)3*3/2log(3)2)
=3
换底公式的应用.