Question

① 要过程啊4[x+3][x-2]-[2X+2分之1][2X-5]=3x-2 ②[3X-1][2X-3]-[6X-5][

Answer 1

（1）原式=（10a-8)(3a-7/2)-(3a-2)(10a-8)

=(10a-8)(3a-3.5-3a+2)=-0.5*(10a-8)

=4-5a

(2)原式=x^4-5x^3+bx^2+ax^3-5ax^2+abx-2x^2+10x-2b

=x^4+(a-5)x^3+(b-5a-2)x^2+(ab+10)x

因为 a-5=0且ab+10=0

所以 a=5,b=-2