Question

设函数f(x)=x的平方-2x+3.x属于闭区间0到3,则该函数的值域为多少

Answer 1

f(x) =x^2-2x+3

=(x-1)^2+2

minf(x) = f1) =2

f(0)=3

f(3)=9-6+3=6

值域=[2,6]