你的题目未完呀,是求通项的么?如果是求通项,
记cn＝a(n+1)－an,则c1＝－2,c2＝－1,则cn＝n－3；
an＝(an－a(n－1))＋(a(n－1)－a(n－2))＋……＋(a2－a1)＋a1＝(n－4－2)(n－1)/2＋6＝(n^2－7n＋18)/2；
同理得：bn＝2＋1/2^(n－3)
设数列An,Bn 满足a1=b1=6,a2=b2=4,a3=b3=3,若{an+1 -an}是等差数列,{bn+1-bn
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