原式=(3x+2)/(x-2)(x+1)+(x+1-1)/(x+1)÷(x-1+1)/(x-1)
=(3x+2)/(x-2)(x+1)+x/(x+1)÷x/(x-1)
=(3x+2)/(x-2)(x+1)+(x-1)/(x+1)
=(3x+2+x²-3x+2)/(x+1)(x-2)
=(x²+4)/(x+1)(x-2)
=(9+4)/(4×1)
=13/4
当x=3时,求下列式子的值∶3x+2／x＾2-x-2+（1-1／x+1）÷（1+1／x-1）
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