Question

①4a^2+2ab+4a+b+1 ②a^2-4ab+4b^2-2a+4b+1因式分解

Answer 1

①4a^2+2ab+4a+b+1

=(4a²+4a+1)+(2ab+b)

=(2a+1)²+b(2a+1)

=(2a+1)(2a+1+b)

②a^2-4ab+4b^2-2a+4b+1

=(a^2-4ab+4b^2)+(-2a+4b)+1

=(a-2b)²-2(a-2b)+1

=(a-2b-1)²