Question

(3/2x+6)-(1/6-2x)+(3/9-x的平方)=?

Answer 1

(3/2x+6)-(1/6-2x)+(3/9-x的平方)

=3/[2(x+3)]-1/[2(3-x)]+3/[(3-x)(3+x)]

=[3(3-x)-(3+x)+3×2]/[2×(3-x)(3+x)]

=2/(3+x)