2倍根号2-3^2010x(2倍根号2+3)^20

2倍根号2-3^2010x(2倍根号2+3)^2011=?

1个回答

(2√2-3)^2010×(2√2+3)^2011
=(2√2-3)^2010×(2√2+3)^2010×(2√2+3)
=[(2√2-3)(2√2+3)]^2010 ×(2√2+3)
=(-1)^2010 ×(2√2+3)
=2√2+3