∵2a-3b+c=0,(1)
3a-2b-6c=0,(2)
∴(1)×6+(2)得:
15a-20b=0
∴a=4/3b
把a=4/3b代入(2)得:
c=1/3b
∴(a^3-2b^3+4c^3)/(a^2b-2b^2c+3ac^2)
=〔(4/3b)^3-2b^3+4(1/3b)^3]/[(4/3b)^2×b-2b^2×(1/3b)+3×(4/3b)×(1/3b)^2]
=(14/27b^3)/(14/9b^3)
=1/3.
∵2a-3b+c=0,(1)
3a-2b-6c=0,(2)
∴(1)×6+(2)得:
15a-20b=0
∴a=4/3b
把a=4/3b代入(2)得:
c=1/3b
∴(a^3-2b^3+4c^3)/(a^2b-2b^2c+3ac^2)
=〔(4/3b)^3-2b^3+4(1/3b)^3]/[(4/3b)^2×b-2b^2×(1/3b)+3×(4/3b)×(1/3b)^2]
=(14/27b^3)/(14/9b^3)
=1/3.