分解因式x^2-y^2-z^2+2yz+x+y-z
3个回答
x^2-y^2-z^2+2yz+x+y-z
=x²-(y-z)²+(x+y-z)
=(x-y+z)(x+y-z)+(x+y-z)
=(x+y-z)(x-y+z+1)
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