首先,原式右边x的3次方项系数是a,所以 a=2
原式等号右边
= 2(x^2-4x+4)(x-2) +b(x^2-4x+4) +cx -c +d
= 2(x^3 -4x^2+4x -2x^2+8x-8) +bx^2-4bx+4b+cx-c+d
= 2x^3 -8x^2+8x-4x^2+16x-16 +bx^2-4bx+4b+cx-c+d
= 2x^3 -(12-b)x^2+(24-4b+c)x -16+4b-c+d
对照等号左边,可得
12-b = 1
24-4b+c = 3
-16+4b-c+d = -5
解之,得 b=11,c=23,d = -10
所以 a =2,b =11,c =2,d = -10
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