Question

有一台电动机,每相电感量0.078H,电阻5Ω,现接在低压380V工频电源上.求电动机三角形接时线电流和有功功率

Answer 1

每相线圈电抗：X = ω * L = 2 * π * f * L = 2 * 3.14 * 50 * 0.078 = 24.5 Ω

电阻：R = 5 Ω

阻抗：Z = （ R * R + X * X）^ 0.5 = 25 Ω

三角形连接,相电压 U = 线电压 = 380

每相电流：I1 = U / Z = 380 / 25 = 15.2 A

线电流：I = √3 * I1 = 1.732 * 15.2 = 26.33 A

功率因数角：P = 3 * I1 * I1 * R = 3 * 15.2 * 15.2 * 5 = 3465.6 w