1.AB在场强方向上的距离为5cm,UAB=0.05*E
2.Ep=φ*q,EpA-EpB=φAq-φBq=q(φA-φB)=q*UAB=
M板电势为0,φM-φA=UAM=0.02E= φA=φM-0.02E=
φB=φA-UAB=φA-0.05*E
1.AB在场强方向上的距离为5cm,UAB=0.05*E
2.Ep=φ*q,EpA-EpB=φAq-φBq=q(φA-φB)=q*UAB=
M板电势为0,φM-φA=UAM=0.02E= φA=φM-0.02E=
φB=φA-UAB=φA-0.05*E