一个圆内的等边三角形ABC,顶点都在圆上,AC长为3,求圆的周长?
圆半径为R
R^2=(R/2)^2+(AC/2)^2=R^2/4+(3/2)^2=R^2/4+1.5^2
R^2=R^2/4+1.5^2
(3*R^2)/4=1.5^2=2.25
3*R^2=9
R^2=3
R=3^0.5
圆的周长=2*PI*R=2*PI*3^0.5=10.883
一个圆内的等边三角形ABC,顶点都在圆上,AC长为3,求圆的周长?
圆半径为R
R^2=(R/2)^2+(AC/2)^2=R^2/4+(3/2)^2=R^2/4+1.5^2
R^2=R^2/4+1.5^2
(3*R^2)/4=1.5^2=2.25
3*R^2=9
R^2=3
R=3^0.5
圆的周长=2*PI*R=2*PI*3^0.5=10.883