化简根号x^2/2y^3(x>0)
1个回答
依题意,y>0
所以:
根号(x^2/2y^3)
=根号[(x^2*2y)/(2y^3*2y)]
=根号[(2x^2*y)/(4y^4)]
=x/(2y^2)*根号(2y)
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