Question

12518X的6次方-6193X的4次方+3697X的2次方-658三0(mod11)

Answer 1

12518=1518=418=88=0(mod11),

6193=693=33=0(mod11),

3697=397=67=1(mod11),

658=108=9(mod11),

12518x^6-6193x^4+3697x^2-658=x^2-9(mod11),

x^2=9(mod11),

设x=11m+r,0