Question

(1/3xy)²*(-12x²y²)÷(-4/3x³y)

Answer 1

(1/3xy)²*(-12x²y²)÷(-4/3x³y)

=1/9*x²y²*(-12x²y²)÷(-4/3x³y)

=[1/9*(-12)÷(-4/3)]*x^(2+2-3)*y^(2+2-1)

=[1/9*12÷4/3]*x*y³

=[4/3*3/4]*x*y³

=xy³