Question

如图已知ab垂直于bca一垂直于edab等于bc角dc135度说明ae=ed

Answer 1

∵∠BCA=∠BAC,AE⊥BC,

∴∠ECA+∠EAC=90°,∠EAC=∠EAB；

∵CD⊥AD,AB⊥AD,

∴CD//AB,∠BCA+∠BAC+∠ACD=180°,∠BAC=∠ACD,

又∠BCA+∠BAC+∠BAC=180°,则∠BAC=∠ACE,

AC=AC,∠AEC+∠ADC=90°,∠BAC=∠ACE,

△ACD≌△ACE,CD=CE.