(1)=2√10-√10/5+3√10=(24√10)/5
(2)=4√5+2√5/125+√5-6√5=(123√5)/125
(3)=(√2+√3)(2√2-2√3)=-2
(4)=7(3+√2)/[(3-√2)(3+√2)]=7(3+√2)/(9-2)=3+√2
(1)=2√10-√10/5+3√10=(24√10)/5
(2)=4√5+2√5/125+√5-6√5=(123√5)/125
(3)=(√2+√3)(2√2-2√3)=-2
(4)=7(3+√2)/[(3-√2)(3+√2)]=7(3+√2)/(9-2)=3+√2