Question

1.当a= 时关于的分式方程(x+1)/(x-2)=(2a-3)/(a+5)的解为0 2.已知x=(t-1)/(t+1)

Answer 1

1.

令X=0 代入方程 得

-1/2=(2a-3)/(a+5)

-a-5=4a-6

5a=1

a=1/5

2.x=(y-1)/(y+1)

x(y+1)=y-1

xy+x-y=-1

(x-1)y+x=-1

y=(x+1)/(1-x)