设总数为X
第一次买了:1/4X+4
剩下:X-(1/4X+4)
第二次卖了:1/2[X-(1/4X+4)]+2
剩下:X-(1/4X+4)- { 1/2[X-(1/4X+4)]+2}
第三次卖出:1/2【X-(1/4X+4)- { 1/2[X-(1/4X+4)]+2} ]
剩下:X-(1/4X+4)- { 1/2[X-(1/4X+4)]+2}
-
1/2【X-(1/4X+4)- { 1/2[X-(1/4X+4)]+2} ]
算一下
这种题有病吧
32个!
设总数为X
第一次买了:1/4X+4
剩下:X-(1/4X+4)
第二次卖了:1/2[X-(1/4X+4)]+2
剩下:X-(1/4X+4)- { 1/2[X-(1/4X+4)]+2}
第三次卖出:1/2【X-(1/4X+4)- { 1/2[X-(1/4X+4)]+2} ]
剩下:X-(1/4X+4)- { 1/2[X-(1/4X+4)]+2}
-
1/2【X-(1/4X+4)- { 1/2[X-(1/4X+4)]+2} ]
算一下
这种题有病吧
32个!