②n(CO2)=2.24L/22.4L/mol=0.1mol 设K2CO3为Xmol,KHCO3ymol,x+y=0.1mo l138x+100y=11.9 得:x=y=0.05mol m(K2CO3)=0.05mol*138g/mol=6.9g m(KHCO3)=5g
C(KOH)=2x+y/0.3L=1mol/L
②n(CO2)=2.24L/22.4L/mol=0.1mol 设K2CO3为Xmol,KHCO3ymol,x+y=0.1mo l138x+100y=11.9 得:x=y=0.05mol m(K2CO3)=0.05mol*138g/mol=6.9g m(KHCO3)=5g
C(KOH)=2x+y/0.3L=1mol/L