1/2∫(sin4x+sin2x)dx 为什么等于

1/2∫(sin4x+sin2x)dx 为什么等于-1/8cos4x-1/4cos2x+c 答案中的1／8和1／4怎么得

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∫ 1/((4(cos x)^2)-((sin x)^2)) dx
(1-cos2x)+sin2x=根号2(sin2x cosπ/4-cos2x sinπ/4)+1 这个是怎么化简得的?
求证（cos^2x-sin^2x)(cos^4x+sin^4x）+1/4sin2xsin4x=cos2x
求解∫1/(cos^4(x)sin^2(x))dx
(1-cos2x)+sin2x=根号2(sin2x cosπ/4-cos2x sinπ/4)+1
y=sin2x-cos2x+1为什么等于√2sin（2x-π/4）+1
f(x)=1-2sin^2(x+π/8)+2sin(x+π/8)*cos(x+π/8)=cos(2x+π/4)+sin(
f(x)=((1+cos2x)^2-2cos2x-1)/(sin(π/4+x)sin(π/4-x))
化简：1.根号下(1-sin^2)2.(1-cos^4x-sin^4x)/(1-cos^6x-sin^6x)
fx=1-2sin^2(x+π/4)+2sin(x+π/8)cos(x+π/8)