Question

2xy^2*(3xy-1/2x^2)= 2ab*5ab^2*3a^2b= 3k(2k-5)+2k(1-3k)=52 k=

Answer 1

2xy^2*(3xy-1/2x^2)= 6x²y³-x³y²

2ab*5ab^2*3a^2b= 30a^4b^8

3k(2k-5)+2k(1-3k)=52 k=?

6k²-15k+2k-6k²=52

-13k=52

k=-4

(-5/2xy)*(2/3xy^2-2xy+4/3y)

=-5/3x²y³+5x²y²-10/3xy²