Question

0.2mol/LNa[Al(OH)4]溶液200ml与0.2mol/L硫酸溶液250ml混合,完全反应后 溶液中三价Al

Answer 1

C（SO42－）＝0.25×0.2＝0.05molC(AlO2-)＝0.2×0.2＝0.04molC(H+)=0.25×0.2×2=0.1molH+＋AlO2－＋H2O＝Al（OH）3（沉淀）0.04 0.04 0.04Al(OH)3+3H+＝Al3＋＋3H2O0.02 0.06 0.02最终C（Al3＋）＝0.02mol C(SO42-...