3(y-2)-(1-y)=8(y-1)
1个回答
3(y-2)-(1-y)=8(y-1)
3y-6-1+y=8y-8
4y-8y= -8+6+1
-4y= -1
y=1/4
相关问题
2y-1/3 -1=5y+1/8 - 3y+1/6
3x-2y=-1(1)2x+3y=8(2)x/2-y/3=1/3(1)3(x-1)=y+1(2)x-3y=2(1)y:x
去分母计算的一元一次方程1-y/3-2y=3-3y+2/4y=?2y-1/3-1=5y+1/8-3y+1/6y=?
由|2y-1/y-2|≤1怎么推出3y2+8y-3≤0
(2x^3y^3-2x^3y+1/8^4+y)/(-1/2x^3y)
求解一个一元五次方,102=8/(1+y)+8/(1+y)^2+8/(1+y)^3+8/(1+y)^4+108/(1+y
4(2y+3)=8(1-y)-5(y-2)
计算:1/(x-y)-1/(x+y)-2y/(x^2+y^2)-4y^3/(x^4+y^4)-8x^7/(x^8+y^8
解方程:2y-1/3-1=5y+1/8-3y+1/6
解下列方程:(1)7(2-3y)-5(2-y)=8(1-7y);(2)[y+2/4]-[2y−3/6]=1.