Question

一元二次方程 用配方法解 1.x^2-2.4x-13=0 2.3/2t^2+4t=1

Answer 1

1、(x-1.2)^2=13+1.44=14.44 x-1.2=3.8或x-1.2=-3.8 x=5或x=-2.6

2、t^2+8t/3=3/2 (t+4/3)^2=22/9 t+4/3=sqrt(22)/3或t+4/3=-sqrt(22)/3 t=[sqrt(22)-4]/3或t=[-sqrt(22)-4]/3