y=3sin(2x+π/5)怎么变化得到y=2si

y=3sin(2x+π/5)怎么变化得到y=2sin(2x+π/4)

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y=sin(π/4+x/2)sin(π/4-x/2) =sin(π/4+x/2)sin[π/2-(π/4+x/2)]
y=sin（x+π/6)如何移动得到y=sin(2x+π/3）
y=2sin三分之一x y=4sin(x-π/3) y=sin(2x+π/6) y=3sin(1/2x-π/4) 的周期
函数Y=2sin3x可看作由Y=2sin(3x+π/4)经过下列变化而得到
y=3sin(2x+π/4)=3sin[2(x+π/8)] 为什么
求值域（1)y=2sin(x/2+π/4)x∈[0,π) (2)y=2cosx-sin^2x+3 x∈[-π/3,2/
求函数y=[sin2x+sin(2x+π/3)-cos1/2﹙π-4x﹚]/[cos2x+cos﹙2x+π/3﹚-sin
y=sin(2x-π/3) 怎么移变成sin2x
y=2cos(x/4+ π/3)-3sin(x- π/4)
√2sin(x/2+π/4)cos(x/2)=√2/2sin(x+π/4)+ 1/2 怎么得到的