Question

用加减法解下列方程组4(x-y-1)=3(1-y)-2,x/2+y/3=2

Answer 1

4(x-y-1)=3(1-y)-2

4x-4y-4=3-3y-2

4x-y=5 (1)

x/2+y/3=2

两边乘6

3x+2y=12 (2)

(1)×2+(2)

8x+3x=10+12

11x=22

所以

x=2

y=4x-5=3