设0.123+0.234+0.345=a,0.234+0.345=b
a-b=(0.123+0.234+0.345)-(0.234+0.345)=0.123
则原式=a×(b+0.456)-(a+0.456)×b
=ab+0.456a-ab-0.456b
=0.456a-0.456b
=0.456(a-b)
=0.456×0.123
=0.056088
（0.125+0.234+0.345）×（0.234+0.345+0.456）减（0.123+0.234+0.345+0
1个回答
相关问题
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0.234×832+0.345×169
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0.123+0.321+0.234+0.432+0.345+0.543+……+0.789+0.987=?
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(1＋123＋234）×（123＋234＋345）－（1＋123＋234＋345）×（123＋234）
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123+234+345+456=?
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123^2+234^2+345^2+2*123*234-2*123*345-2*234*345
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1.345 × 0.345× 2.69 -1.345×1.345-1.345×0.345×0.345
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0.345²+1.345²－0.345×2.69
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1.345×0.345×2.69-1.345^3-1.345×0.345^2
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计算:1.345×0.345×2.69-1.345²-1.345×0.345²×2
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123+234+345=？