左边=sin[(x+a/2)+a/2]-sin[(x+a/2)-a/2]
=[sin(x+a/2)cosa/2+cos(x+a/2)sina/2]-[sin(x+a/2)cosa/2-cos(x+a/2)sina/2]
=2cos(x+a/2)sina/2
左边=sin[(x+a/2)+a/2]-sin[(x+a/2)-a/2]
=[sin(x+a/2)cosa/2+cos(x+a/2)sina/2]-[sin(x+a/2)cosa/2-cos(x+a/2)sina/2]
=2cos(x+a/2)sina/2