Question

已知f(x)=ax的五次方+bx的三次方+1且f（5）=7,则f（-5）=

Answer 1

已知：f(x)=ax^5+bx^3+1∴f（-x）=a（-x）^5+b（-x）^3+1=-ax^5-bx^3-1+2=-（ax^5+bx^3+1）+2=-f（x）+2又f（5）=7,∴f（-5）=-f（5）+2=-7+2=-5