Question

2^2*16^(3/4）+2log根号2+1/2log25+(logπ)^0

Answer 1

原题log的底=?

假设为10,

原题=2^2*16^(3/4）+2lg根号2+1/2lg25+(lgπ)^0

=2^2*(2^4)^(3/4）+lg(根号2)^2+lg(25)^(1/2)+1

=2^2*2^(4*3/4）+lg2+lg5+1

=2^2*2^3+lg2*5+1

=4*8+lg10+1

=32+1+1

=34