下面各题怎样简便就怎样算. 25×13×4 135+39+55+61 35×201 2000÷25÷8 17×43-43

1个回答

  • 解题思路:(1)根据乘法交换律进行计算;

    (2)根据加法交换律和结合律进行计算;

    (3)根据乘法分配律进行计算;

    (4)根据连除的性质进行计算;

    (5)根据乘法分配律进行计算;

    (6)根据连减的性质进行计算.

    (1)25×13×4,

    =25×4×13,

    =100×13,

    =1300;

    (2)135+39+55+61,

    =(135+55)+(39+61),

    =190+100,

    =290;

    (3)35×201,

    =35×(200+1),

    =35×200+35×1,

    =7000+35,

    =7035;

    (4)2000÷25÷8,

    =2000÷(25×8),

    =2000÷200,

    =10;

    (5)17×43-43×7,

    =(17-7)×43,

    =10×43,

    =430;

    (6)278-122-78,

    =278-(122+78),

    =278-200,

    =78.

    点评:

    本题考点: 整数四则混合运算;运算定律与简便运算.

    考点点评: 四则运算,先弄清运算顺序,然后再进一步计算,能简算的要简算.