Question

4x^3-8x^2+4xa^2-2a(b+c)+(b+c)^2x^2+3x+2m^2-4m+3x^2-3xy+2y^2x

Answer 1

4x^3-8x^2+4x=4x(x²-2x+1)=4x(x-1)²

a^2-2a(b+c)+(b+c)^2=[a-(b+c)]²=(a-b-c)²

x^2+3x+2=(x+1)(x+2)

m^2-4m+3=(m-1)(m-3)

x^2-3xy+2y^2=(x-y)(x-2y)

x^2y^2-5x^2y-6x^2=x²(y²-5y-6)=x²(y-6)(y+1)