Question

四道数学方程题.（1）y^2-2√2y+2=0（2）2-1/3x^2=5/3x（3）x^2-6x+10=0（4）(x-2

Answer 1

1）y^2-2√2y+2=0

(y-√2)^2=0

y=√2

（2）2-1/3x^2=5/3x

6-x^2=5x

(x-1)(x+6)=0

x1=1

x2=-6

（3）x^2-6x+10=0

(x-3)^2+1=0

无解

（4）(x-2)(2x-3)=6

2x^2-7x+6=6

x(2x-7)=0

x1=0

x2=3.5