Question

初一的几道计算题-3又5/8+3又1/12-19/8-25/12（1又4/5-2又5/6+3又7/10-4又8/15）÷

Answer 1

-3又5/8+3又1/12-19/8-25/12

=-29/8-19/8+37/12-25/12

=-48/8+12/12

=-6+1

=-5

(1又4/5-2又5/6+3又7/10-4又8/15)/(-1/30)

=(1又4/5-2又5/6+3又7/10-4又8/15)×(-30）

=-1又4/5×30+2又5/6×30-3又7/10×30+4又8/15×30

=-54+85-111+136

=56

[(1-1/3)的2次方-(-1又2/3)÷(-1又1/8)]×(-1又1/2)的3次方

=[(2/3)的2次方-(-5/3)÷(-9/8)]×(-27/8)

=[4/9-40/27]×(-27/8)

=-4/9×27/8+40/27×27/8

=-1.5+5

=3.5