Question

在△ABC中,AB=BC=AC,∠ABC=∠C=60°,BD=CE,AD与BE相交于点P,求∠APE的度数

Answer 1

BD=CE AB=BC =∠C=60°

所以△ABD全等于△BCE ,∠BAD=∠CBE

∠APE=∠ABP+∠BAD=∠ABP+∠CBE=∠ABC=60°,